1.7 G Lioh (2024)

FAQs

What is the molarity of a solution containing 16.7 grams of NH in 1.50 liters of solution? ›

What is the molarity of a solution containing 16.7 grams of NH3 in 1.50 liters of solution? 0.0653 M.

You're correct that you would need 83.3 mL of 12.0 M HCl to make 1.00 L of 1.00 M HCl .

Systems at equilibrium can be disturbed by changes to temperature, concentration, and, in some cases, volume and pressure; volume and pressure changes will disturb equilibrium if the number of moles of gas is different on the reactant and product sides of the reaction.

Final answer:

To make a 0.215 M LiCl solution when diluted to 300.0 mL, 107.5 mL of a 0.600 M LiCl solution is required, based on the dilution equation M1V1 = M2V2.

The most common way to express solution concentration is molarity (M), which is defined as the amount of solute in moles divided by the volume of solution in liters: M = moles of solute/liters of solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

We should divide the number of moles of acid by the volume in liters of acid. Now that we've determined the molar concentration of the hydrochloric acid solution, we must round our answer to three decimal places. The result is 0.073 moles per liter.

To obtain the Molarity of Concentrated acid, this simple formula can be applied: %purity*specific gravity*10 divided by Molar mass of the acid. from 35% HCl, the mass of the solution is 100g the mass of HCl is 35 g, and the density is 1.18g/ml. The same is true for other percentages of HCl.

0.47 L of 8.0 M HCl are needed to prepare 1.50 L of 2.5 M HCl.

Only three types of stresses can change the composition of an equilibrium mixture: (1) a change in the concentrations (or partial pressures) of the components by adding or removing reactants or products, (2) a change in the total pressure or volume, and (3) a change in the temperature of the system.

When a chemical system at equilibrium is disturbed, it returns to equilibrium by counteracting the disturbance. As described in the previous paragraph, the disturbance causes a change in Q; the reaction will shift to re-establish Q=K.

What effect will adding more NH3 g have on the equilibrium? ›

Short Answer. a) Adding more NH3(g) will shift the equilibrium towards the reactants (left), favoring the formation of NH4HS(s). b) Adding more NH4HS(s) will have no effect on the equilibrium position.

Answer and Explanation:

We need to dilute 3.00 mL of the stock solution to 60.0 mL to acquire the desired solution concentration.

Answer and Explanation:

From the balanced chemical equation, there is a 1:1 mole ratio between the two reactants. We will use this mole ratio to determine the volume of NaOH needed to react with the given amount of H N O 3 . Approximately 21 mL of 3.0 M NaOH will react completely with 4.0 mL of 16 M H N O 3 .

Here, M is the molarity of the solution, n is defined as the number of solute and V is the volume of the solution in liters. Hence we can say that 1.117 liters of a 0.88 M solution can be made with 25.5 gram of lithium fluoride.

The molarity of the solution is 2.0 mol/L.

Number of moles of NH3 = Mass of NH3 / Molar mass of NH3= 17.0 g / 17.04 g/mol= 0.998 molNow, we need to find the volume of solution in liters. The volume of solution is given as 1200. mL, which is equal to 1.2 L. Molarity = moles of solute / volume of solution (in liters)= 0.998 mol / 1.2 L= 0.831 M.

what is the molarity of a solution that contains 17 g of NH3 in 0.50 L of solution? 17g NH3 divided by 17g/mol will give you 1 mol NH3. 17 is the molar mass for NH3. Since your 0.5L is already in liters and you now know your moles (1 mole) simply divide.

Answer and Explanation:

Firstly, we will convert the mass into the mol. Therefore, the molarity of solution produced when 3.65 g of HCl are dissolved in 2 L of water = 0.05 M.